ГДЗ по алгебре 9 класс Мерзляк Задание 477

\[\boxed{\text{477}\text{\ (477)}\text{.\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[x^{2} + 6x - 2 = 0\]

\[D = 36 + 8 = 44\]

\[x_{1,2} = \frac{- 6 \pm \sqrt{44}}{2}\]

\[x_{1} = \frac{- 6 + 2\sqrt{11}}{2} = - 3 + \sqrt{11}\]

\[x_{2} = \frac{- 6 - 2\sqrt{11}\ }{2} = - 3 - \sqrt{11}\]

\[x_{1}^{2} + x_{2}^{2} = \left( - 3 + \sqrt{11} \right)^{2} +\]

\[+ \left( - 3 - \sqrt{11} \right)^{2} =\]

\[= 9 - 6\sqrt{11} + 11 + 9 +\]

\[+ 6\sqrt{11} + 11 = 40\]

\[Ответ:40.\]