\[\boxed{\text{160\ (160).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
Пояснение.
Решение.
\[\textbf{а)}\ \sqrt[4]{16} = \sqrt[4]{2^{4}} = 2\]
\[\textbf{б)}\ \sqrt[5]{32} = \sqrt[5]{2^{5}} = 2\]
\[\textbf{в)}\ \sqrt[12]{1} = 1\]
\[\textbf{г)}\ \sqrt[3]{- \frac{1}{8}} = \ \sqrt[3]{\left( - \frac{1}{2} \right)^{3}} = - \frac{1}{2}\]
\[\textbf{д)}\ \sqrt[4]{5\frac{1}{16}} = \sqrt[4]{\frac{81}{16}} = \sqrt[4]{\left( \frac{3}{2} \right)^{4}} = \frac{3}{2}\]
\[\textbf{е)}\ \sqrt[3]{3\frac{3}{8}} = \sqrt[3]{\frac{27}{8}} = \sqrt[3]{\left( \frac{3}{2} \right)^{3}} = \frac{3}{2}\ \]