\[\boxed{\text{191\ (191).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
Пояснение.
Решение.
\[\textbf{а)}\ \sqrt{1,3} = {1,3}^{\frac{1}{2}};\]
\[\textbf{б)}\ \sqrt[3]{7^{- 1}} = 7^{- \frac{1}{3}};\]
\[\textbf{в)}\ \sqrt[4]{\frac{2}{3}} = \left( \frac{2}{3} \right)^{\frac{1}{4}};\]
\[\textbf{г)}\ \sqrt[5]{\left( \frac{3}{2} \right)^{- 2}} = \sqrt[5]{\left( \frac{2}{3} \right)^{2}} = \left( \frac{2}{3} \right)^{\frac{2}{5}};\]
\[\textbf{д)}\ \sqrt[7]{a^{4}} = a^{\frac{4}{7}};\]
\[\textbf{е)}\ \frac{1}{\sqrt[4]{x^{3}}} = \frac{1}{x^{\frac{3}{4}}\text{\ \ }} = x^{- \frac{3}{4}};\]
\[\textbf{ж)}\ \sqrt[3]{a^{2} - b^{2}} = \left( a^{2} - b^{2} \right)^{\frac{1}{3}};\]
\[\textbf{з)}\ \sqrt[5]{(x - y)^{2}\ } = (x - y)^{\frac{2}{5}}.\]