\[\boxed{\text{216}\text{\ (216)}\text{.}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[2px^{2} - 2x - 2p - 3\]
\[x_{1} = 0:\ \]
\[2p \cdot 0^{2} - 2 \cdot 0 - 2p - 3 = 0\]
\[- 2p - 3 = 0\]
\[2p = - 3\]
\[p = - 1,5.\]
\[Подставим:\]
\[2 \cdot ( - 1,5)x^{2} - 2x - 2 \cdot\]
\[\cdot ( - 1,5) - 3 = 0\]
\[- 3x^{2} - 2x = 0\]
\[3x^{2} + 2x = 0\]
\[x(3x + 2) = 0\]
\[x_{1} = 0;\ \ x_{2} = - \frac{2}{3}.\]
\[Ответ:при\ p = - 1,5;\ \ \]
\[x = 0;\ \ x = - \frac{2}{3}.\]