ГДЗ по алгебре 9 класс Макарычев Задание 225

\[\boxed{\text{225}\text{\ (225)}\text{.}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[mx^{2} + (m - 3)x - 3 = 0\]

\[D = (m - 3)^{2} + 4 \cdot 3 \cdot m =\]

\[= m^{2} - 6m + 9 + 12m =\]

\[= m^{2} + 6m + 9 =\]

\[= (m + 3)^{2} > 0 - два\ корня.\]

\[x_{1} = \frac{- m + 3 + m + 3}{2m} =\]

\[= \frac{6}{2m} = \frac{3}{m};\]

\[x_{2} = \frac{- m + 3 - m - 3}{2m} =\]

\[= \frac{- 2m}{2m} = - 1.\]

\[m = - 3 \rightarrow x_{1} = - 1;\]

\[m = - 1 \rightarrow \text{\ \ }x_{1} = - 3;\]

\[m = 3 \rightarrow \text{\ \ }x_{1} = 1;\]

\[m = 1 \rightarrow \text{\ \ }x_{1} = 3.\]