\[\boxed{\text{326\ (326).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
Пояснение.
Решение.
\[\textbf{а)}\ (x + 25)(x - 30) < 0\]
\[x \in ( - 25;30).\]
\[\textbf{б)}\ (x + 6)(x - 6) > 0\]
\[x \in ( - \infty;\ - 6) \cup (6; + \infty).\]
\[\textbf{в)}\ \left( x - \frac{1}{3} \right)\left( x - \frac{1}{5} \right) \leq 0\]
\[(x - 0,2)\left( x - \frac{1}{3} \right) \leq 0\]
\[x \in \left\lbrack 0,2;\frac{1}{3} \right\rbrack.\]
\[\textbf{г)}\ (x + 0,1)(x + 6,3) \geq 0\]
\[(x + 6,3)(x + 0,1) \geq 0\]
\[x \in ( - \infty;\ - 6,3\rbrack \cup \lbrack - 0,1; + \infty).\]