\[\boxed{\text{884\ (884).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[\textbf{а)}\ \frac{\sqrt{\sqrt{18} - 3} \cdot \sqrt{\sqrt{18} + 3}}{\sqrt{6}} = \sqrt{1,5}\]
\[\frac{\sqrt{\sqrt{18} - 3} \cdot \sqrt{\sqrt{18} + 3}}{\sqrt{6}} = \sqrt{1,5}\]
\[\frac{\sqrt{\left( \left( \sqrt{18} \right)^{2} - 3^{2} \right)}}{\sqrt{6}} = \sqrt{1,5}\]
\[\frac{\sqrt{9}}{\sqrt{6}} = \sqrt{1,5}\]
\[\sqrt{\frac{3}{2}} = \sqrt{1,5}\]
\[\sqrt{1,5} = \sqrt{1,5}.\]
\[\textbf{б)}\ \frac{\sqrt{10}}{\sqrt{7 + \sqrt{24}} \cdot \sqrt{7 - \sqrt{24}}} = \sqrt{0,4}\]
\[\ \frac{\sqrt{10}}{\sqrt{7 + \sqrt{24}} \cdot \sqrt{7 - \sqrt{24}}} = \sqrt{0,4}\]
\[\frac{\sqrt{10}}{\sqrt{\left( 7^{2} - \left( \sqrt{24} \right)^{2} \right)}} = \sqrt{0,4}\]
\[\frac{\sqrt{10}}{\sqrt{49 - 24}} = \sqrt{0,4}\]
\[\sqrt{\frac{10}{25}} = \sqrt{0,4}\]
\[\sqrt{0,4} = \sqrt{0,4}.\]