\[\boxed{\mathbf{1126.ОК\ ГДЗ - домашка\ на}\ 5}\]
\[Рисунок\ по\ условию\ задачи:\]
\[\mathbf{Дано:}\]
\[R = 10\ см;\]
\[\cup AB = 60{^\circ}.\]
\[\mathbf{Найти:}\]
\[S_{ост} - ?\]
\[\mathbf{Решение.}\]
\[1)\ S_{ост} = S_{кр} - S_{\text{AB}}.\]
\[2)\ S_{кр} = \pi R^{2} = 3,14 \bullet 10^{2} =\]
\[= 3,14 \bullet 100 = 314\ см^{2}.\]
\[3)\ S_{\text{AB}} = \frac{\pi R^{2}}{360{^\circ}} \bullet \alpha =\]
\[= \frac{3,14 \bullet 100}{360{^\circ}} \bullet 60{^\circ} = 52,33\ см^{2}.\]
\[4)\ S_{ост} = 314 - 52,33 =\]
\[= 261,67\ см^{2}.\]
\[Ответ:S_{ост} = 261,67\ см^{2}.\]