\[\boxed{\mathbf{548.ОК\ ГДЗ - домашка\ на}\ 5}\]
\[Рисунок\ по\ условию\ задачи:\]
\[\mathbf{Дано:}\]
\[\mathrm{\Delta}\text{ABC}\sim\mathrm{\Delta}A_{1}B_{1}C_{1};\]
\[\frac{\text{BC}}{B_{1}C_{1}} = k;\]
\[\text{BC} = 1,4\ м;\]
\[B_{1}C_{1} = 56\ см.\]
\[\mathbf{Найти:}\]
\[\frac{P_{\text{ABC}}}{P_{A_{1}B_{1}C_{1}}} - ?\]
\[\mathbf{Решение.}\]
\[1)\frac{\text{BC}}{B_{1}C_{1}} = \frac{140}{56} = 2,5;\]
\[k = 2,5.\]
\[2)\ \mathrm{\Delta}\text{ABC}\sim\mathrm{\Delta}A_{1}B_{1}C_{1}\ (по\ условию):\]
\[\frac{P_{\text{ABC}}}{P_{A_{1}B_{1}C_{1}}} = k\]
\[\frac{P_{\text{ABC}}}{P_{A_{1}B_{1}C_{1}}} = 2,5.\]
\[\mathbf{Ответ:}2,5\mathbf{.}\]