\[\boxed{\mathbf{748.ОК\ ГДЗ - домашка\ на}\ 5}\]
\[Рисунок\ по\ условию\ задачи:\]
\[Дано:\]
\[ABCD - параллелограмм;\]
\[\text{AC\ }и\ BD - диагонали;\]
\[AC \cap BD = O.\]
\[Равны\ ли\ векторы:\]
\[\textbf{а)}\ \overrightarrow{\text{AB}}\ и\ \overrightarrow{\text{DC}}:\]
\[\overrightarrow{\text{AB}} = \overrightarrow{\text{DC}}.\]
\[\textbf{б)}\ \overrightarrow{\text{BC}}\ и\ \overrightarrow{\text{DA}}:\]
\[\overrightarrow{\text{BC}} \neq \overrightarrow{\text{DA}}.\]
\[\textbf{в)}\ \overrightarrow{\text{AO}}\ и\ \overrightarrow{\text{OC}}:\]
\[\overrightarrow{\text{AO}} = \overrightarrow{\text{OC}}.\]
\[\textbf{г)}\ \overrightarrow{\text{AC}}\ и\ \overrightarrow{\text{BD}}:\]
\[\overrightarrow{\text{AC}}\ и\ \overrightarrow{\text{BD}} - не\ коллинеарны;\]
\[\overrightarrow{\text{AC}} \neq \overrightarrow{\text{BD}}.\]
\[Ответ:а)\ да;б)\ нет;в)\ да;\]
\[\textbf{г)}\ нет.\]