ГДЗ по геометрии 9 класс Атанасян Задание 1101

\[\boxed{\mathbf{1101.ОК\ ГДЗ - домашка\ на}\ 5}\]

\[\mathbf{Формула}\mathbf{:\ \ \ }\]

\[C = 2\pi R \Longrightarrow \ R = \frac{C}{2\pi};\]

\[где\ \ \ \pi = 3,14.\]

\[1)\ C = 2 \bullet 3,14 \bullet 4 = 25,12;\]

\[2)\ C = 2 \bullet 3,14 \bullet 3 = 18,84;\]

\[3)\ R = \frac{82}{2 \bullet 3,14} = 13,06;\]

\[4)\ R = \frac{18\pi}{2\pi} = 9;\]

\[5)\ C = 2 \bullet 3,14 \bullet 0,7 = 4,4;\]

\[6)\ R = \frac{6,28}{2 \bullet 3,14} = 1;\]

\[7)\ C = 2 \bullet 3,14 \bullet 101,5 = 637,42;\]

\[8)\ C = 2 \bullet 3,14 \bullet 2\frac{1}{3} = 14,65;\]

\[9)\ R = \frac{2\sqrt{2}}{2 \bullet 3,14} = 0,45.\]