ГДЗ по математике 6 класс Мерзляк ФГОС Задание 346

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\[1)\ \frac{4}{7} \cdot \frac{3}{5} = \frac{4 \cdot 3}{7 \cdot 5} = \frac{12}{35}\]

\[2)\ \frac{8}{27} \cdot \frac{3}{4} = \frac{8 \cdot 3}{27 \cdot 4} = \frac{2}{9}\]

\[3)\ 9\frac{3}{5} \cdot \frac{10}{21} = \frac{48}{5} \cdot \frac{10}{21} = \frac{48 \cdot 10}{5 \cdot 21} =\]

\[= \frac{16 \cdot 2}{1 \cdot 7} = \frac{32}{7} = 4\frac{4}{7}\]

\[4)\ 1\frac{5}{7} \cdot 6\frac{1}{8} = \frac{12}{7} \cdot \frac{49}{8} = \frac{12 \cdot 49}{7 \cdot 8} =\]

\[= \frac{3 \cdot 7}{1 \cdot 2} = \frac{21}{2} = 10\frac{1}{2}\]

\[5)\ 4\frac{1}{2} \cdot 3\frac{1}{3} = \frac{9}{2} \cdot \frac{10}{3} = \frac{9 \cdot 10}{2 \cdot 3} =\]

\[= 3 \cdot 5 = 15\]

\[6)\ 2\frac{1}{4} \cdot \frac{16}{27} \cdot 4\frac{1}{3} = \frac{9}{4} \cdot \frac{16}{27} \cdot \frac{13}{3} =\]

\[= \frac{9 \cdot 16 \cdot 13}{4 \cdot 27 \cdot 3} = \frac{1 \cdot 4 \cdot 13}{1 \cdot 3 \cdot 3} = \frac{52}{9} =\]

\[= 5\frac{7}{9}\]