ГДЗ по математике 6 класс Мерзляк ФГОС Задание 398

\[\boxed{\mathbf{398}\mathbf{.}}\]

\[1)\ \left( 3\frac{1}{3} \right)^{2} - 2\frac{13}{16} \cdot 2\frac{2}{5} =\]

\[= \left( \frac{10}{3} \right)^{2} - \frac{45}{16} \cdot \frac{12}{5} =\]

\[= \frac{100}{9} - \frac{9 \cdot 3}{4 \cdot 1} = 11\frac{1}{9} - \frac{27}{4} =\]

\[= 11\frac{1^{\backslash 4}}{9} - 6\frac{3^{\backslash 9}}{4} =\]

\[= 11\frac{4}{36} - 6\frac{27}{36} = 10\frac{40}{36} - 6\frac{27}{36} =\]

\[= 4\frac{13}{36}\]

\[2)\ 5 \cdot \left( \frac{9}{14} + \frac{5^{\backslash 2}}{7} \right) - 1\frac{1}{3}\ :\frac{56}{75} =\]

\[= 5 \cdot \left( \frac{9}{14} + \frac{10}{14} \right) - \frac{4}{3} \cdot \frac{75}{56} =\]

\[= 5 \cdot \frac{19}{14} - \frac{1 \cdot 25}{1 \cdot 14} = \frac{95}{14} - \frac{25}{14} =\]

\[= \frac{70}{14} = 5\]