2) $$\frac{1,2}{\frac{1}{6}}=\frac{2,4}{2y+3}$$

$$\frac{1,2}{\frac{1}{6}}=\frac{2,4}{2y+3}$$ Разделим 1,2 на 1/6: $$1,2 : \frac{1}{6} = 1,2 \cdot 6 = 7,2$$ Получим: $$7,2 = \frac{2,4}{2y+3}$$ $$7,2(2y+3) = 2,4$$ $$14,4y + 21,6 = 2,4$$ $$14,4y = 2,4 - 21,6$$ $$14,4y = -19,2$$ $$y = \frac{-19,2}{14,4}$$ $$y = -\frac{192}{144}$$ $$y = -\frac{4}{3}$$ $$y = -1 \frac{1}{3}$$ Ответ: $$\textbf{y = -1 \frac{1}{3}}$$