65. 2) 1\frac{1}{22} \cdot 3\frac{2}{3} - (2\frac{5}{6} + 3\frac{5}{6} - \frac{7}{23}) \cdot \frac{3}{5};

1) $$1\frac{1}{22} \cdot 3\frac{2}{3} - (2\frac{5}{6} + 3\frac{5}{6} - \frac{7}{23}) \cdot \frac{3}{5} = \frac{1 \cdot 22 + 1}{22} \cdot \frac{3 \cdot 3 + 2}{3} - (\frac{2 \cdot 6 + 5}{6} + \frac{3 \cdot 6 + 5}{6} - \frac{7}{23}) \cdot \frac{3}{5} = \frac{23}{22} \cdot \frac{11}{3} - (\frac{17}{6} + \frac{23}{6} - \frac{7}{23}) \cdot \frac{3}{5} = \frac{23 \cdot 11}{22 \cdot 3} - (\frac{17 + 23}{6} - \frac{7}{23}) \cdot \frac{3}{5} = \frac{23}{2 \cdot 3} - (\frac{40}{6} - \frac{7}{23}) \cdot \frac{3}{5} = \frac{23}{6} - (\frac{20}{3} - \frac{7}{23}) \cdot \frac{3}{5} = \frac{23}{6} - (\frac{20 \cdot 23}{3 \cdot 23} - \frac{7 \cdot 3}{23 \cdot 3}) \cdot \frac{3}{5} = \frac{23}{6} - (\frac{460}{69} - \frac{21}{69}) \cdot \frac{3}{5} = \frac{23}{6} - \frac{439}{69} \cdot \frac{3}{5} = \frac{23}{6} - \frac{439 \cdot 3}{69 \cdot 5} = \frac{23}{6} - \frac{439}{23 \cdot 5} = \frac{23}{6} - \frac{439}{115} = \frac{23 \cdot 115}{6 \cdot 115} - \frac{439 \cdot 6}{115 \cdot 6} = \frac{2645}{690} - \frac{2634}{690} = \frac{2645 - 2634}{690} = \frac{11}{690} \approx 0,016$$.

Ответ: \(\approx 0,016\)