Вопрос:

9$$\frac{3}{4}$$ + 3$$\frac{1}{6}$$. 7$$\frac{3}{8}$$ + 9$$\frac{7}{16}$$ + 11$$\frac{7}{12}$$. 6$$\frac{19}{48}$$ - 5$$\frac{11}{32}$$.

Ответ:

1) 9$$\frac{3}{4}$$ + 3$$\frac{1}{6}$$ = 9 + $$\frac{3}{4}$$ + 3 + $$\frac{1}{6}$$ = 12 + $$\frac{3}{4}$$ + $$\frac{1}{6}$$ = 12 + $$\frac{9}{12}$$ + $$\frac{2}{12}$$ = 12 + $$\frac{11}{12}$$ = 12$$\frac{11}{12}$$. 2) 7$$\frac{3}{8}$$ + 9$$\frac{7}{16}$$ + 11$$\frac{7}{12}$$ = 7 + $$\frac{3}{8}$$ + 9 + $$\frac{7}{16}$$ + 11 + $$\frac{7}{12}$$ = 27 + $$\frac{3}{8}$$ + $$\frac{7}{16}$$ + $$\frac{7}{12}$$ = 27 + $$\frac{18}{48}$$ + $$\frac{21}{48}$$ + $$\frac{28}{48}$$ = 27 + $$\frac{67}{48}$$ = 27 + 1$$\frac{19}{48}$$ = 28$$\frac{19}{48}$$. 3) 6$$\frac{19}{48}$$ - 5$$\frac{11}{32}$$ = 6 + $$\frac{19}{48}$$ - 5 - $$\frac{11}{32}$$ = 1 + $$\frac{19}{48}$$ - $$\frac{11}{32}$$ = 1 + $$\frac{19 \cdot 2}{48 \cdot 2}$$ - $$\frac{11 \cdot 3}{32 \cdot 3}$$ = 1 + $$\frac{38}{96}$$ - $$\frac{33}{96}$$ = 1 + $$\frac{5}{96}$$ = 1$$\frac{5}{96}$$.
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