3) $$3\frac{11}{24} + \frac{1}{6}$$. ж) $$17\frac{2}{3} - 6\frac{7}{8}$$; 3) $$24\frac{7}{15} - 15\frac{5}{12}$$.

3) $$3\frac{11}{24} + \frac{1}{6} = 3\frac{11}{24} + \frac{4}{24} = 3\frac{15}{24} = 3\frac{5}{8}$$

ж) $$17\frac{2}{3} - 6\frac{7}{8} = 17\frac{16}{24} - 6\frac{21}{24} = 16\frac{40}{24} - 6\frac{21}{24} = 10\frac{19}{24}$$

3) $$24\frac{7}{15} - 15\frac{5}{12} = 24\frac{28}{60} - 15\frac{25}{60} = 9\frac{3}{60} = 9\frac{1}{20}$$

Ответ:

$$3\frac{11}{24} + \frac{1}{6} = 3\frac{5}{8}$$

$$17\frac{2}{3} - 6\frac{7}{8} = 10\frac{19}{24}$$

$$24\frac{7}{15} - 15\frac{5}{12} = 9\frac{1}{20}$$