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МатематикаВопрос:
15) $$\frac{7}{a^3} = \frac{...}{4a^3}$$
Ответ:
$$\frac{7}{a^3} = \frac{28}{4a^3}$$
Похожие
- 9) $$ rac{3}{a} = \frac{...}{5a}$$
- 10) $$\frac{4}{x} = \frac{...}{3x}$$
- 11) $$\frac{2}{y} = \frac{...}{16y}$$
- 12) $$\frac{7}{b} = \frac{...}{4b}$$
- 13) $$\frac{1}{x^2} = \frac{...}{2x^2}$$
- 14) $$\frac{5}{y^2} = \frac{...}{15y^2}$$
- 15) $$\frac{7}{a^3} = \frac{...}{4a^3}$$
- 16) $$\frac{2}{x^4} = \frac{...}{5x^4}$$
- $$\frac{a}{b} = \frac{...}{b^3}$$
- $$\frac{a}{b} = \frac{...}{10b^3}$$
- $$\frac{x}{y} = \frac{...}{y^2}$$
- $$\frac{x}{y} = \frac{...}{4y^3}$$
- $$\frac{2}{x} = \frac{...}{2xy^2}$$
- $$\frac{2}{x} = \frac{...}{3x^2y^2}$$
- $$\frac{7b}{a} = \frac{...}{ab}$$
- $$\frac{7b}{a} = \frac{...}{3a^2b^2}$$
- $$\frac{a^2}{2x} = \frac{...}{8xa^2}$$
- $$\frac{a^2}{2x} = \frac{...}{6x^2a}$$
