39. ($$\frac{2}{9}$$x²y)² ⋅ (-9xy²)³ = ($$\frac{2}{9}$$)² ⋅ (x²)² ⋅ y² ⋅ (-9)³ ⋅ x³ ⋅ (y²)³ = $$\frac{4}{81}$$ ⋅ x⁴ ⋅ y² ⋅ (-729) ⋅ x³ ⋅ y⁶ = -$$\frac{4}{81}$$ ⋅ 729 ⋅ x⁴ ⋅ x³ ⋅ y² ⋅ y⁶ = -36x⁷y⁸
Ответ: -36x⁷y⁸