32. ($$\frac{2}{5}$$xy²) ⋅ (-$$\frac{5}{4}$$xy²) = $$\frac{2}{5}$$ ⋅ (-$$\frac{5}{4}$$) ⋅ x ⋅ x ⋅ y² ⋅ y² = -$$\frac{1}{2}$$x²y⁴
Ответ: -$$\frac{1}{2}$$x²y⁴