$$\frac{(2^3)^4 \times (2^5)^2}{2 \times (2^3)^5} = \frac{2^{3 \times 4} \times 2^{5 \times 2}}{2 \times 2^{3 \times 5}} = \frac{2^{12} \times 2^{10}}{2 \times 2^{15}} = \frac{2^{12+10}}{2^{1+15}} = \frac{2^{22}}{2^{16}} = 2^{22-16} = 2^6 = 64$$
Ответ: 64