3¹⁰×(3²)³ 5)

$$\frac{3^{10} \times (3^2)^3}{3 \times (3^5)^2} = \frac{3^{10} \times 3^{2 \times 3}}{3 \times 3^{5 \times 2}} = \frac{3^{10} \times 3^6}{3 \times 3^{10}} = \frac{3^{10+6}}{3^{1+10}} = \frac{3^{16}}{3^{11}} = 3^{16-11} = 3^5 = 243$$

Ответ: 243