3) $$ \frac{108 \cdot 6^7 - 108 \cdot 6^6}{216^3 - 36^4} = \frac{108 \cdot 6^6 (6 - 1)}{(6^3)^3 - (6^2)^4} = \frac{108 \cdot 6^6 \cdot 5}{6^9 - 6^8} = \frac{108 \cdot 6^6 \cdot 5}{6^8 (6-1)} = \frac{108 \cdot 6^6 \cdot 5}{6^8 \cdot 5} = \frac{108 \cdot 6^6}{6^8} = \frac{108}{6^2} = \frac{108}{36} = 3 $$
Ответ: 3