12. 6 3√4-3√37 ⋅ 3√16+4 3√37 + 3√37².

12. $$6 \sqrt[3]{4} - \sqrt[3]{37} \cdot \sqrt[3]{16} + 4 \sqrt[3]{37} + \sqrt[3]{37^2} = 6 \sqrt[3]{4} - \sqrt[3]{37} \cdot (4 \sqrt[3]{37} + \sqrt[3]{37^2} + \sqrt[3]{16})$$.

Ответ: 6$$\sqrt[3]{4} - \sqrt[3]{37} \cdot (4 \sqrt[3]{37} + \sqrt[3]{37^2} + \sqrt[3]{16})$$