10.√36a² + 12ab + b² при а=и= 8. 5

10. $$ \sqrt{36a^2 + 12ab + b^2} $$ при $$ a = 4 \frac{4}{5} $$ и $$ b = 8 \frac{1}{5} $$.

$$ \sqrt{36a^2 + 12ab + b^2} = \sqrt{(6a)^2 + 2 \cdot 6a \cdot b + b^2} = \sqrt{(6a + b)^2} = |6a + b| $$

$$ 6a + b = 6 \cdot 4 \frac{4}{5} + 8 \frac{1}{5} = 6 \cdot \frac{24}{5} + \frac{41}{5} = \frac{144}{5} + \frac{41}{5} = \frac{185}{5} = 37 $$

Ответ: 37