№ 16 1) √252 ; 2) 5,6⋅10³ 3) 2 log₆12 2 √7 4⋅10⁻¹

• $$\frac{\sqrt{252}}{2\sqrt{7}} = \frac{\sqrt{36 \cdot 7}}{2\sqrt{7}} = \frac{6\sqrt{7}}{2\sqrt{7}} = 3 $$
• $$\frac{5,6 \cdot 10^3}{4 \cdot 10^{-1}} = \frac{5,6 \cdot 10^3 \cdot 10^1}{4} = \frac{5,6 \cdot 10^4}{4} = 1,4 \cdot 10^4 = 14000$$
• $$2 \log_6 12 = \log_6 12^2 = \log_6 144 = \log_6 6^2 \cdot 4 = 2 + \log_6 4 =2 + \log_6 2^2=2 + 2\log_6 2 $$

Ответ: 1) 3; 2) 14000; 3)$$2 + 2\log_6 2 $$