Решение №4

$$\frac{0,2a^{8}b^{-10}}{1,7a^{-6}b^{12}} = \frac{0,2}{1,7}\cdot\frac{a^{8}}{a^{-6}}\cdot\frac{b^{-10}}{b^{12}} = \frac{2}{17}\cdot a^{8-(-6)}\cdot b^{-10-12} = \frac{2}{17}a^{14}b^{-22} = \frac{2a^{14}}{17b^{22}}$$