Ответ:

Преобразуем числа: \(-0.3=-\frac{3}{10}\), \(4\frac{2}{7}=\frac{30}{7}\), \(0.8=\frac{4}{5}\), \(-4\frac{1}{2}=-\frac{9}{2}\).

\(\frac{1}{6}\left(-\frac{3}{10}+\frac{30}{7}\right)-\frac{4}{5}\left(-\frac{9}{2}\right)=\frac{1}{6}\cdot\frac{279}{70}+\frac{18}{5}=\frac{93}{140}+\frac{504}{140}=\frac{597}{140}=4\frac{37}{140}.\)

Ответ: \(4\frac{37}{140}\).