Вопрос:

1.262. Найдите среднее арифметическое следующих чисел: а) 1 и 9; б) 1, 2 и 3; в) 0, 7 и 8; г) 1, 2, 88, 557, 1000; д) 1/2 и 1/3; е) 1 3/4 и 2 2/3; ё) 2 3/10, 1 4/15 и 2 7/30; ж) 1/36 и 5/48; з) 1/2 и 0,5; и) 1/3 и 0,4; й) 5/7, 1,4 и 2,3; к) 0,25 и 1 2/3; л) 0,01, 0,1 и 1; м) 2,3, 2,03 и 2,003; н) 5,7 и 5/7; о) 1/2, 1/3, 1/4 и 1/5; п) 1,5 и 2 1/4; р) 7 1/2 и 4,1; с) 5 1/6, 1,25 и 3,5; т) 0,54, 1 4/5 и 2,46.

Ответ:

  1. \(\frac{1+9}{2}=5\).
  2. \(\frac{1+2+3}{3}=2\).
  3. \(\frac{0+7+8}{3}=5\).
  4. \(\frac{1+2+88+557+1000}{5}=329.6\).
  5. \(\frac{\frac12+\frac13}{2}=\frac5{12}\).
  6. \(\frac{\frac74+\frac83}{2}=\frac{53}{24}=2\frac5{24}\).
  7. \(\frac{\frac{23}{10}+\frac{19}{15}+\frac{67}{30}}{3}=\frac{19}{9}=2\frac19\).
  8. \(\frac{\frac1{36}+\frac5{48}}2=\frac{19}{288}\).
  9. \(\frac{\frac12+0.5}{2}=0.5\).
  10. \(\frac{\frac13+0.4}{2}=\frac{11}{30}\).
  11. \(\frac{\frac57+1.4+2.3}{3}=\frac{47}{21}=2\frac5{21}\).
  12. \(\frac{0.25+\frac53}{2}=\frac{23}{24}\).
  13. \(\frac{0.01+0.1+1}{3}=0.37\).
  14. \(\frac{2.3+2.03+2.003}{3}=2.111\).
  15. \(\frac{5.7+\frac57}{2}=\frac{109}{35}=3\frac4{35}\).
  16. \(\frac{\frac12+\frac13+\frac14+\frac15}{4}=\frac{77}{240}\).
  17. \(\frac{1.5+2.25}{2}=1.875=1\frac78\).
  18. \(\frac{7.5+4.1}{2}=5.8\).
  19. \(\frac{\frac{31}{6}+1.25+3.5}{3}=\frac{119}{36}=3\frac{11}{36}\).
  20. \(\frac{0.54+1.8+2.46}{3}=1.6\).