1. (a1-g4-7) Tenglamani yeching: $\frac{2(3x+4)+3(2x+4)}{-3(2x+4)+4(2x-3)}=\frac{4}{3}$. A) 4; B) $\frac{4}{7}$; C) −2; D) $\frac{156}{28}$.

Question

Вопрос: $Фото задания: 1. (a1-g4-7) Tenglamani yeching: $\frac{2(3x+4)+3(2x+4)}{-3(2x+4)+4(2x-3)}=\frac{4}{3}$. A) 4; B) $\frac{4}{7}$; C) −2;…$ Фото задания

1. (a1-g4-7) Tenglamani yeching: $\frac{2(3x+4)+3(2x+4)}{-3(2x+4)+4(2x-3)}=\frac{4}{3}$. A) 4; B) $\frac{4}{7}$; C) −2; D) $\frac{156}{28}$.

Accepted Answer

Avval surat va maxrajni soddalashtiramiz:

$2(3x+4)+3(2x+4)=12x+20$,

$-3(2x+4)+4(2x-3)=2x-24$. Maxraj nol bo‘lmasligi uchun $x\ne12$.

$\frac{12x+20}{2x-24}=\frac{4}{3}$

$3(12x+20)=4(2x-24)$

$36x+60=8x-96$

$28x=-156$, demak $x=-\frac{156}{28}=-\frac{39}{7}$. Bu qiymat $x\ne12$ shartini qanoatlantiradi.

Javob: $x=-\frac{39}{7}$. Ko‘rinib turgan D variantida minus belgisi bo‘lmasa, variantlarda to‘g‘ri javob yo‘q; D varianti $-\frac{156}{28}$ bo‘lishi kerak.

1. (a1-g4-7) Tenglamani yeching: \(\frac{2(3x+4)+3(2x+4)}{-3(2x+4)+4(2x-3)}=\frac{4}{3}\). A) 4; B) \(\frac{4}{7}\); C) −2; D) \(\frac{156}{28}\).

Ответ: