Ответ:
Birinchi qavsni umumiy maxrajga keltiramiz:
\(\frac{x}{x-1}-\frac{x}{x+1}=\frac{x(x+1)-x(x-1)}{(x-1)(x+1)}=\frac{2x}{x^2-1}\).
Ikkinchi kasrning maxrajini soddalashtiramiz: \(x-\frac1x=\frac{x^2-1}{x}\), shuning uchun \(\frac{1}{x-\frac1x}=\frac{x}{x^2-1}\).
Endi bo‘lamiz: \(\frac{2x}{x^2-1}:\frac{x}{x^2-1}=2\) (ifoda aniqlangan qiymatlarda).
Javob: B) 2.
