1. Найдите значение выражения: 1) \(\dfrac{-3\frac{1}{3}\cdot\left(-2\frac{4}{5}\right):\dfrac{-6,8}{0,9}-1\frac{7}{9}\\cdot(-0,75):\left(-\frac{1}{6}\right)}{-8\frac{1}{3}\cdot16,2:(-22,5)}\); 2) \(\dfrac{-1\frac{1}{3}\cdot\left(2+0,9\cdot\left(-\frac{5}{9}\right)\right):\left(-\frac{4}{9}\right)-2,7}{\left(-2\frac{4}{7}\cdot0,58-0,42\cdot2\frac{4}{7}\right)\cdot1\frac{5}{9}:(-2\frac{2}{3})}\).

1)

Числитель:

\(-3\frac{1}{3}\cdot\left(-2\frac{4}{5}\right):\frac{-6,8}{0,9}=\frac{-10}{3}\cdot\frac{-14}{5}:\frac{-34}{5}=-\frac{70}{51}\).

\(1\frac{7}{9}\cdot(-0,75):\left(-\frac{1}{6}\right)=\frac{16}{9}\cdot\left(-\frac{3}{4}\right):\left(-\frac{1}{6}\right)=\frac{13}{2}\).

Числитель равен: \(-\frac{70}{51}-\frac{13}{2}=-\frac{803}{102}\).

Знаменатель:

\(-8\frac{1}{3}\cdot16,2:(-22,5)=-\frac{25}{3}\cdot\frac{81}{5}:\left(-\frac{45}{2}\right)=6\).

\(\frac{-803/102}{6}=-\frac{803}{612}\).

2)

\(2+0,9\cdot\left(-\frac{5}{9}\right)=2-0,5=1,5=\frac{3}{2}\).

Числитель:

\(-1\frac{1}{3}\cdot\frac{3}{2}:\left(-\frac{4}{9}\right)-2,7=-2:\left(-\frac{4}{9}\right)-\frac{27}{10}=\frac{9}{2}-\frac{27}{10}=\frac{9}{5}\).

Знаменатель:

\(-2\frac{4}{7}\cdot0,58-0,42\cdot2\frac{4}{7}=-\frac{18}{7}\cdot\frac{29}{50}-\frac{21}{50}\cdot\frac{18}{7}=-\frac{18}{7}\).

\(-\frac{18}{7}\cdot1\frac{5}{9}:(-2\frac{2}{3})=-\frac{18}{7}\cdot\frac{14}{9}:\left(-\frac{8}{3}\right)=\frac{3}{2}\).

\(\frac{9/5}{3/2}=\frac{6}{5}=1,2\).

Ответ: 1) \(-\frac{803}{612}\); 2) \(\frac{6}{5}=1,2\).