а) 3 \frac{3}{10} \cdot 2 \frac{1}{6} = \frac{33}{10} \cdot \frac{13}{6} = \frac{33 \cdot 13}{10 \cdot 6} = \frac{11 \cdot 13}{10 \cdot 2} = \frac{143}{20} = 7 \frac{3}{20}
б) 3 \frac{3}{5} : 2 \frac{1}{10} = \frac{18}{5} : \frac{21}{10} = \frac{18}{5} \cdot \frac{10}{21} = \frac{18 \cdot 10}{5 \cdot 21} = \frac{6 \cdot 2}{1 \cdot 7} = \frac{12}{7} = 1 \frac{5}{7}
в) 7 \frac{8}{15} \cdot 1 \frac{2}{13} - 3 \frac{17}{20} \cdot \frac{1}{13} = \frac{113}{15} \cdot \frac{15}{13} - \frac{77}{20} \cdot \frac{1}{13} = \frac{113}{13} - \frac{77}{260} = \frac{113 \cdot 20}{13 \cdot 20} - \frac{77}{260} = \frac{2260}{260} - \frac{77}{260} = \frac{2260 - 77}{260} = \frac{2183}{260} = 8 \frac{63}{260}
Ответ: а) 7 \frac{3}{20}, б) 1 \frac{5}{7}, в) 8 \frac{63}{260}