1. Вычислите: а) \(3\frac{3}{4}+2\frac{4}{7}\); б) \(2\frac{4}{9}-1\frac{5}{6}\).

а) \(3\frac{3}{4}+2\frac{4}{7}=5+\frac{3}{4}+\frac{4}{7}=5+\frac{21}{28}+\frac{16}{28}=5\frac{37}{28}=6\frac{9}{28}\).

б) \(2\frac{4}{9}-1\frac{5}{6}=1+\frac{4}{9}-\frac{5}{6}=1+\frac{8}{18}-\frac{15}{18}=1-\frac{7}{18}=\frac{11}{18}\).

Ответ: а) \(6\frac{9}{28}\); б) \(\frac{11}{18}\).