1. Вычисления:
- a) \(\frac{5}{9} + \frac{5}{6} - \frac{3}{4} + \frac{3}{5} \cdot \frac{2}{3} = \frac{5}{9} + \frac{5}{6} - \frac{3}{4} + \frac{2}{5} = \frac{100 + 150 - 135 + 72}{180} = \frac{187}{180} = 1 \frac{7}{180}\)
- б) \(\frac{5}{6} - \frac{3}{4} = \frac{10 - 9}{12} = \frac{1}{12}\)
- в) \(\frac{3}{4} \cdot \frac{2}{9} : 1 = \frac{3 \cdot 2}{4 \cdot 9} = \frac{6}{36} = \frac{1}{6}\)
- г) \(\frac{7}{9} : \frac{2}{3} = \frac{7}{9} \cdot \frac{3}{2} = \frac{21}{18} = \frac{7}{6} = 1 \frac{1}{6}\)
Ответ: а) \(1 \frac{7}{180}\); б) \(\frac{1}{12}\); в) \(\frac{1}{6}\); г) \(1 \frac{1}{6}\).