Решение:
- а) \(\frac{5}{6} \cdot \frac{3}{20} = \frac{5 \cdot 3}{6 \cdot 20} = \frac{15}{120} = \frac{1}{8}\)
- б) \(\frac{3}{7} \cdot \frac{6}{11} = \frac{3 \cdot 6}{7 \cdot 11} = \frac{18}{77}\)
- в) \(\frac{10}{11} \cdot \frac{11}{26} = \frac{10 \cdot 11}{11 \cdot 26} = \frac{10}{26} = \frac{5}{13}\)
- г) \(\frac{3}{7} \cdot \frac{14}{15} = \frac{3 \cdot 14}{7 \cdot 15} = \frac{3 \cdot 2 \cdot 7}{7 \cdot 3 \cdot 5} = \frac{2}{5}\)
- д) \(\frac{24}{65} \cdot \frac{39}{40} = \frac{24 \cdot 39}{65 \cdot 40} = \frac{3 \cdot 8 \cdot 3 \cdot 13}{5 \cdot 13 \cdot 5 \cdot 8} = \frac{9}{25}\)
- е) \(4 \cdot \frac{4}{21} = \frac{4}{1} \cdot \frac{4}{21} = \frac{4 \cdot 4}{1 \cdot 21} = \frac{16}{21}\)
- ж) \(\frac{7}{18} \cdot 6 = \frac{7}{18} \cdot \frac{6}{1} = \frac{7 \cdot 6}{18 \cdot 1} = \frac{7 \cdot 1}{3 \cdot 1} = \frac{7}{3}\)
- и) \(2\frac{1}{7} \cdot 1\frac{1}{5} = \frac{15}{7} \cdot \frac{6}{5} = \frac{15 \cdot 6}{7 \cdot 5} = \frac{3 \cdot 5 \cdot 6}{7 \cdot 5} = \frac{18}{7}\)
- к) \(3\frac{1}{9} \cdot 21 = \frac{28}{9} \cdot 21 = \frac{28 \cdot 21}{9} = \frac{28 \cdot 7 \cdot 3}{3 \cdot 3} = \frac{196}{3}\)
- л) \(2\frac{2}{15} \cdot 1\frac{9}{16} = \frac{32}{15} \cdot \frac{25}{16} = \frac{32 \cdot 25}{15 \cdot 16} = \frac{2 \cdot 16 \cdot 5 \cdot 5}{3 \cdot 5 \cdot 16} = \frac{10}{3}\)
- м) \(1\frac{1}{7} \cdot 3\frac{1}{2} = \frac{8}{7} \cdot \frac{7}{2} = \frac{8 \cdot 7}{7 \cdot 2} = \frac{8}{2} = 4\)
Ответ: а) \(\frac{1}{8}\), б) \(\frac{18}{77}\), в) \(\frac{5}{13}\), г) \(\frac{2}{5}\), д) \(\frac{9}{25}\), е) \(\frac{16}{21}\), ж) \(\frac{7}{3}\), и) \(\frac{18}{7}\), к) \(\frac{196}{3}\), л) \(\frac{10}{3}\), м) 4