10) 1 9/19 · 2 12/32 =

\(1\dfrac{9}{19}=\dfrac{28}{19},\quad 2\dfrac{12}{32}=2\dfrac{3}{8}=\dfrac{19}{8}\)

\(\dfrac{28}{19}\cdot\dfrac{19}{8}=\dfrac{28}{8}=\dfrac{7}{2}=3\dfrac{1}{2}\)

Ответ: \(3\dfrac{1}{2}\)