2) 3 13/25 − 7/28 =

\(3\dfrac{13}{25}-\dfrac{7}{28}=3\dfrac{13}{25}-\dfrac{1}{4}\)

\(\dfrac{13}{25}-\dfrac{1}{4}=\dfrac{52-25}{100}=\dfrac{27}{100}\)

Ответ: \(3\dfrac{27}{100}\)