Ответ:

  1. а) \(\left(\frac{5}{12}+\frac{3}{8}\right)\cdot\frac{12}{19}=\left(\frac{10}{24}+\frac{9}{24}\right)\cdot\frac{12}{19}=\frac{19}{24}\cdot\frac{12}{19}=\frac{1}{2}\).
  2. б) \(\frac{6}{7}\cdot\left(\frac{11}{18}-\frac{5}{12}\right)=\frac{6}{7}\cdot\left(\frac{22}{36}-\frac{15}{36}\right)=\frac{6}{7}\cdot\frac{7}{36}=\frac{1}{6}\).
  3. в) \(\left(\frac{43}{14}-\frac{19}{7}\right)\cdot\left(7-\frac{33}{5}\right)=\frac{5}{14}\cdot\frac{2}{5}=\frac{1}{7}\).
  4. г) \(\left(\frac{37}{12}-\frac{11}{4}\right)\cdot\left(\frac{7}{6}-\frac{5}{12}\right)=\frac{1}{3}\cdot\frac{3}{4}=\frac{1}{4}\).
  5. д) \(\left(\frac{79}{12}-\frac{86}{15}\right)\cdot\left(\frac{20}{17}-\frac{10}{17}\right)=\frac{17}{20}\cdot\frac{10}{17}=\frac{1}{2}\).
  6. е) \(\frac{2}{3}\cdot\frac{9}{16}-\frac{5}{24}\cdot\frac{2}{5}-\frac{1}{6}=\frac{3}{8}-\frac{1}{12}-\frac{1}{6}=\frac{9}{24}-\frac{2}{24}-\frac{4}{24}=\frac{1}{8}\).

Ответ: а) \(\frac{1}{2}\); б) \(\frac{1}{6}\); в) \(\frac{1}{7}\); г) \(\frac{1}{4}\); д) \(\frac{1}{2}\); е) \(\frac{1}{8}\).