12. Вычислите: \(1\frac{4}{9} : \left(\frac{8}{7}-\frac{19}{6}\right)+13\cdot1\frac{2}{5}\).

\[\frac{8}{7}-\frac{19}{6}=\frac{48-133}{42}=-\frac{85}{42}.\]

\[1\frac{4}{9}=\frac{13}{9},\qquad \frac{13}{9}:\left(-\frac{85}{42}\right)=\frac{13}{9}\cdot\left(-\frac{42}{85}\right)=-\frac{182}{255}.\]

\[13\cdot1\frac{2}{5}=13\cdot\frac{7}{5}=\frac{91}{5}.\]

\[-\frac{182}{255}+\frac{91}{5}=\frac{-182+4641}{255}=\frac{4459}{255}.\]

Ответ: \(\frac{4459}{255}\).