Вопрос:

13. Вычислите: \(2\frac{7}{10} : \left(\frac{9}{13}-\frac{29}{4}\right)+18\cdot1\frac{3}{8}\).

Ответ:

\[\frac{9}{13}-\frac{29}{4}=\frac{36-377}{52}=-\frac{341}{52}.\]

\[2\frac{7}{10}=\frac{27}{10},\qquad \frac{27}{10}:\left(-\frac{341}{52}\right)=\frac{27}{10}\cdot\left(-\frac{52}{341}\right)=-\frac{702}{1705}.\]

\[18\cdot1\frac{3}{8}=18\cdot\frac{11}{8}=\frac{99}{4}.\]

\[-\frac{702}{1705}+\frac{99}{4}=\frac{-2808+168795}{6820}=\frac{165987}{6820}.\]

Ответ: \(\frac{165987}{6820}\).