Ответ:\(3(v+5)-2(v-6)=3v+15-2v+12=v+27\).\(2y(x-y)+y(3y-2x)=2xy-2y^2+3y^2-2xy=y^2\).\(3p(8c+1)-8c(3p-5)=24pc+3p-24pc+40c=3p+40c\).\(n(n^2-n)+(n^2-n+1)=n^3-n^2+n^2-n+1=n^3-n+1\).