Ответ:Let y = (x-1)/2. Then 2y² + 2y - 6 = 0, or y² + y - 3 = 0.y = (-1 ± sqrt(1 - 4(1)(-3)))/2 = (-1 ± sqrt(13))/2(x-1)/2 = (-1 ± sqrt(13))/2x-1 = -1 ± sqrt(13)x = ±sqrt(13)