Ответ:(x-1)(x+2)² = 4(x+2)(x-1)(x+2)² - 4(x+2) = 0(x+2)[(x-1)(x+2) - 4] = 0(x+2)(x² + x - 2 - 4) = 0(x+2)(x² + x - 6) = 0(x+2)(x+3)(x-2) = 0x = -2, x = -3, x = 2