Ответ:
\(\sqrt{98}=7\sqrt{2}\), \(\sqrt{32}=4\sqrt{2}\).
\((7\sqrt{2}-4\sqrt{2})\cdot4\sqrt{2}=3\sqrt{2}\cdot4\sqrt{2}=12\cdot2=24\).
Ответ: 24
\(\sqrt{98}=7\sqrt{2}\), \(\sqrt{32}=4\sqrt{2}\).
\((7\sqrt{2}-4\sqrt{2})\cdot4\sqrt{2}=3\sqrt{2}\cdot4\sqrt{2}=12\cdot2=24\).
Ответ: 24