2) $(2\frac{5}{6}+1\frac{7}{9})\cdot3\frac{3}{5}-(2\frac{5}{6}-1\frac{7}{9})\cdot2\frac{16}{19}$

Question

Вопрос: $Фото задания: 2) $(2\frac{5}{6}+1\frac{7}{9})\cdot3\frac{3}{5}-(2\frac{5}{6}-1\frac{7}{9})\cdot2\frac{16}{19}$$ Фото задания

Accepted Answer

$2\frac{5}{6}+1\frac{7}{9}=\frac{17}{6}+\frac{16}{9}=\frac{83}{18}$.

$\frac{83}{18}\cdot3\frac{3}{5}=\frac{83}{18}\cdot\frac{18}{5}=\frac{83}{5}$.

$2\frac{5}{6}-1\frac{7}{9}=\frac{17}{6}-\frac{16}{9}=\frac{19}{18}$.

$\frac{19}{18}3\cdot2\frac{16}{19}=\frac{19}{18}\cdot\frac{54}{19}=3$.

$\frac{83}{5}-3=\frac{68}{5}=13\frac{3}{5}$.

Ответ: $13\frac{3}{5}$.

2) \((2\frac{5}{6}+1\frac{7}{9})\cdot3\frac{3}{5}-(2\frac{5}{6}-1\frac{7}{9})\cdot2\frac{16}{19}\)