2/7 · 16/35 + 1/4 =

\[\frac{2}{7}\cdot\frac{16}{35}+\frac{1}{4}=\frac{32}{245}+\frac{1}{4}=\frac{128+245}{980}=\frac{373}{980}\]

Ответ: \(\frac{373}{980}\)