2) \(\frac{3}{34}+\frac{11}{20}-\frac{10}{17}\)

\[\frac{3}{34}-\frac{10}{17}=\frac{3}{34}-\frac{20}{34}=-\frac{17}{34}=-\frac{1}{2}\]

\[-\frac{1}{2}+\frac{11}{20}=-\frac{10}{20}+\frac{11}{20}=\frac{1}{20}\]

Ответ: \(\frac{1}{20}\)