2) \(\left[\left(4\frac{6}{7}-1\frac{11}{14}\right)\cdot4\frac{2}{3}+\left(3\frac{2}{9}-1\frac{6}{9}\right)\cdot\frac{18}{25}\right]\)

Question

Вопрос:

Accepted Answer

Преобразуем смешанные числа:

\(4\frac{6}{7}-1\frac{11}{14}=\frac{34}{7}-\frac{25}{14}=\frac{43}{14}\).

\(\frac{43}{14}\cdot4\frac{2}{3}=\frac{43}{14}\cdot\frac{14}{3}=\frac{43}{3}\).

\(3\frac{2}{9}-1\frac{6}{9}=\frac{29}{9}-\frac{15}{9}=\frac{14}{9}\).

\(\frac{14}{9}\cdot\frac{18}{25}=\frac{28}{25}\).

\(\frac{43}{3}+\frac{28}{25}=\frac{1075}{75}+\frac{84}{75}=\frac{1159}{75}=15\frac{34}{75}\).

Ответ: \(\frac{1159}{75}=15\frac{34}{75}\).