2. Представьте в виде дроби: a) \(\frac{3-2a}{2a} - \frac{1-a^{2}}{a^{2}}\) б) \(\frac{1}{3x+y} - \frac{1}{3x-y}\) в) \(\frac{4-8b}{b^{2}-2b} + \frac{3}{b-2}\)

2. Представьте в виде дроби:

1. а)

   \(\frac{3-2a}{2a} - \frac{1-a^{2}}{a^{2}} = \frac{a(3-2a) - 2(1-a^{2})}{2a^{2}} = \frac{3a-2a^{2}-2+2a^{2}}{2a^{2}} = \frac{3a-2}{2a^{2}}\)

2. б)

   \(\frac{1}{3x+y} - \frac{1}{3x-y} = \frac{(3x-y) - (3x+y)}{(3x+y)(3x-y)} = \frac{3x-y-3x-y}{9x^{2}-y^{2}} = \frac{-2y}{9x^{2}-y^{2}}\)

3. в)

   \(\frac{4-8b}{b^{2}-2b} + \frac{3}{b-2} = \frac{4(1-2b)}{b(b-2)} + \frac{3}{b-2} = \frac{4-8b+3b}{b(b-2)} = \frac{4-5b}{b(b-2)}\)

Ответ: а) \(\frac{3a-2}{2a^{2}}\), б) \(\frac{-2y}{9x^{2}-y^{2}}\), в) \(\frac{4-5b}{b(b-2)}\)